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IBM C1000-112 Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Quantum Computing Fundamentals | - Qubits and quantum states - Superposition and entanglement - Measurement and collapse |
| Noise and Real Hardware | - IBM Quantum hardware execution - Quantum noise and error sources |
| Quantum Gates and Circuits | - Quantum circuit construction - Single-qubit gates (X, Y, Z, H) - Multi-qubit gates (CNOT, controlled operations) |
| Quantum Algorithms | - Basic algorithmic complexity concepts - Deutsch-Jozsa algorithm - Grover's search algorithm |
| Qiskit Programming | - Qiskit Terra basics - Building and executing circuits - Simulators and Aer backend usage |
IBM Fundamentals of Quantum Computation Using Qiskit v0.2X Developer Sample Questions:
What is the primary function of visualizations in quantum computing?
- A. To simplify mathematical equations in quantum algorithms
- B. To provide a graphical representation of quantum states and operations
- C. To enhance the aesthetic appeal of quantum algorithms
- D. To represent classical bits as qubits in quantum systems
Correct Answer: B 🗳️
What system information can be retrieved using the show_backend_properties() function in Qiskit?
- A. System software updates and patches
- B. Specifics about quantum hardware, such as gate errors and connectivity
- C. Details on user accounts
- D. Information on quantum circuit gates and operations
Correct Answer: B 🗳️
Which of the following bloch_multivector plot options given below is the correct one for the given bell quantum circuit?
qc = QuantumCircuit(2)
qc.x(0)
qc.h(0)
qc.h(1)
- A.
- B.
- C.
- D.
Correct Answer: B 🗳️
Which line of code would assign a unitary simulator object to the variable backend?
- A. backend = BasicAer.UnitarySimulatorPy()
- B. backend = BasicAer.get_backend('unitary_simulator')
- C. backend = BasicAer.get_back('unitary_simulator')
- D. backend = BasicAer.get_back_unitary_simulator()
Correct Answer: B 🗳️
In the below code snippet, what is the probability of measuring |0>?
qc = QuantumCircuit(1)
qc.ry(3*math.pi/4, 0)
- A. 1.0
- B. 0.8536
- C. 0.5
- D. 0.1464
Correct Answer: D 🗳️
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